A chord of a circle of radius 6cm is making an angle 60°at the centre.Find the length of the chord
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IN TRIANGLE AOB, AO=BO=6cm
THEREFORE,∠OAB=∠OBA=y(say)
IN TRIANGLE AOB BY ANGLE SUM PROPERTY
60°+y+y=180°⇒180°-60°=2y⇒120°=2y⇒y=60°
THEREFORE AS ∠A=∠B=∠C=60°
THEREFORE TRIANGLE AOB IS AN EQUILATERAL TRIANGLE
⇒LENGTH OF CHORD AB =6cm.
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