a chord of a circle of radius 8 cm subtends an angle of 60°.Find the area of the minor segment
Answers
Answer:
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Step-by-step explanation:
A chord of 8 cms long subtends 60 degree angle at the center, then the Largest Chord i.e the Diameter, as we know makes 180 degree angle at the Center, here the length of that Chord will be 180/60 x 8 =…. As under....
180/60 x 8 cms = 3 x 8 = 24 cms. Then the radius ( radius is half of the Diameter or twice the length of radius) will be… 24/2….
Radius is 12 cms. Answer.
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Area of sector ABCD =πr^2¢/360°
=)22/7×15×15×60°/360°
=)117.85.
Area of ∆ABC.
=1/2r^2sin¢
=)1/2×15×15×√3/2
=)225√3/4
=)97.3125.
minor segment BDC=Area of sector ABDC-Area of triangle ABC.
=117.85-97.3125
=)20.53 ___1)
and again ,Area of circle =πr^2¢
=)22/7×15×15
=)707.14.cm^2.
.
so, major segment BDC
=)Area of circle - minor segment.
=)707.14-20.5
=)686.642 Ans