A chord of a circle of radius 9 cm subtends a right angle at the centre. Find the area of the corresponding minor segment & major sector.
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In the mentioned circle,
O is the centre and AO =BO = Radius = 10 cm
AB is a chord which subtents 90o at centre O, i.e., ∠AOB=90o
(i)
Area of minor segment APB (Shaded region) = Area of Sector AOB - Area of △AOB
=(4π×10×10)−(0.5×10×10)
=78.5−50
=28.5cm2
(ii)
Area of Major sector = Area of circle - Area of Sector AOB
= (π×10×10)−(4π×10×10)
=314−78.5
=235.5cm2
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