A chord of a circle of radius is 10cm substend a right angle at the centre .find the area of corresponding minor and major segment
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area of segment= area of sector- area of ∆
ar of sector=teeta/360×πr^2
90÷360×22÷7×100
550/7
area of ∆= 1/2 b×h
1/2×10×10
50cm
area of segment=550÷7-50cm
ar of sector=teeta/360×πr^2
90÷360×22÷7×100
550/7
area of ∆= 1/2 b×h
1/2×10×10
50cm
area of segment=550÷7-50cm
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