Question

A chord of a circle subtends an angle of theta at the centre of the circle. The area of the minor Segment out off by the Chord is one eighth of the area of the circle.
Prove that 8 sin theta upon 2 cos theta upon 2 +π = π theta upon 45
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Answer 1

Answer:

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Step-by-step explanation:

A chord of a circle subtends an angle of θ at the centre of the circle. The area of minor segment cut off by the chord is one eighth of the area of the circle. Prove that 8sin2θcos2θ+π=45πθ.