Question

A chord of a circle with radius 14cm subtends 120 angle at the centre find the corresponding major segment of the circle

Answer 1

Answer:

Step-by-step explanation:

Radius of circle= 14cm.

Angel subtained by cord in the center= 120°.

Now let us name the center as O, and cord as A and B.

Join AO and BO.

Now AOB is an isosceles triangle.

Therefore, angle OAB=angle OBA.

Therefore angle OAB =(180-120) /2=30°

Now from O draw a line perpendicular to AB which cut AB at D.

Now AD= AO cos 30= 14 cos30 = 2.15 cm.

Therefore length of the cord 2×2.15=4.3cm.