a chord of circle of radius 10 centimetre subtended a right angle at the centre find the area of major sector
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Answer:
Step-by-step explanation:
Let AB be the chord of the circle subtending 90° angle at centre O of the circle.
Area of major sector OADB =
=3/4 x 3.14 x 10 x 10
=235.5cm2
Area of minor sector OACB =
=1/4 x 3.14 x 10 x 10
= 78.5cm2
Area of trangle OAB =
=50 cm2
Area of minor segment ACB = Area of minor sector OACB - Area of ΔOAB = 78.5 - 50 = 28.5 cm2
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