a chord of circle of radius 10 cm subtend right angle at the centre find the area of corresponding minor segment
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Answer:
answer 200/7
Step-by-step explanation:
given
radius 10
thitha 90°
then we know that
are of minor segment= πr square thitha/360 -1/2 r square sin thitha
22/7×10×10×90/360 -1/2×10×10×1
550/7-50
550-350/7
220/7
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