A chord of circle of radius 10 cm subtends a rigjt angle at the centre. the area of corresponding minor segment is
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mudunuriprudhvi19:
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Area of sector = thita/360* πr²
=90/360*22/7*10²
=1/4*22/7*100
= 1/2*11/7*100
= 1100/14cm²
Area of trangle =1/2*base*height
=1/2*10*10
=50cm²
Area of minor segment= 1100/14-50
= 1100-70\14
= 1030/14cm²
=90/360*22/7*10²
=1/4*22/7*100
= 1/2*11/7*100
= 1100/14cm²
Area of trangle =1/2*base*height
=1/2*10*10
=50cm²
Area of minor segment= 1100/14-50
= 1100-70\14
= 1030/14cm²
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