Question

a chord of circle of radius 14 cm subtends a right angle at the center.what is the area of minor sector ? π=22/7

Answer 1

Chord subtends 90° angle at centre. Therefore area of minor sector = π x (radius)^2 x (90° / 360°)

= (22/7) x (14)^2 x (1/4)

= 154 cm^2.

Answer 2

Answer:

Hey, I am here to help you......

OA=OB=14cm.

teta= 90 degree.

Area of segment APB= area of sector OAPB- area of triangle AOB.

90/360* 22/7* 14* 14.

9/36* 22/1* 7* 14.

1/2* 11* 7* 14.

1* 11* 7* 7.

11* 7* 7.

77* 7.

539cm^2.

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