Question

A chord of circle of radius 14cm subtends an right angle at the center.Find the area of the minor sector.​

Answer 1

Answer:

154 cm²

Step-by-step explanation:

Radius of circle = 14 cm

Angle subtended = 90° = α

Method 1 ---

Area of minor sector = $\frac{\pi r^{2} \alpha }{360}$ = $\frac{22}{7} * 14 * 14 * \frac{90}{360}$ = 22 x 7 = 154 cm²

Method 2 ---

Since, the angle formed is 90°, therefore, the minor sector is a quadrant.

Area of quadrant = $\frac{\pi r^{2} }{4} = \frac{22}{7} * 14 *\frac{14}{4}$ = 22 x 7 = 154 cm²

Hope this helps.....