Question

A chord of circle of radius 20 cm subtends an angle π/2 at the centre of the circle. find the area of minor segment formed by this chord.

Answer 1

r = 20cm 

A = 90 degree

Area of sector = A/360×πr²

= (90/360)×(22/7)×20×20

= (1/4)×(22/7)×20×20

= 2200/7

= 314.2 cm²

Area of triangle = 1/2×bh

= 1/2×20×20

= 200 cm²

Area of minor segment = 314.2 - 200

= 114.2 cm²

Major Segment = area of circle - 114.2

= πr² - 114.2

= 22/7 ×20×20 -114.2 

= 1142 .94 cm²