Question

A chord of circle of radius 20cm subtends an angle of 90 at centre of circle.find corresponding major segment

Answer 1

heya it's Aastha....

r = 20cm 
theta = 90 degree
area of sector = theta/360 * pi * r2
= 90/360 * 22/7 * 20 * 20
= 1/4 * 22/7 * 20 * 20
= 2200/7
314.2 cm2
area of triangle = 1/2 * base * height
= 1/2 * 20 * 20 ( base and height both are r ) = 200 cm2
Area of minor segment = 314.2 - 200 = 114.2 cm2
major segment = area of circle - 114.2
= pi * r2 - 114.2
=22/7 * 20 * 20 -114.2 
= 1142 .94 cm2

Hope it help you

Answer 2

Answer:

this answer was correct