a chord of lenght 30 cm is drawn in a circle of tadius 17 cm find its distance from the centre of the circle
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8 cm is its distance.
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triangle OAP In the pic forms a right triangle.
using Pythagoras theorem,
OA^2=AP^2+OP^2
WE Know,OP divides the chord into halves.
AP=15 cm
we know AP,OA
R.T.Find:OP
BY THEORM,
17^2=15^2+OP^2
289=225+OP^2
289-225=OP^2
OP^2=64
OP=√64
OP=8 cm...
so,distance from center to chord is 8 cm....
hope it helps...
: )
PLEASE MARK ME BRAINLIST
using Pythagoras theorem,
OA^2=AP^2+OP^2
WE Know,OP divides the chord into halves.
AP=15 cm
we know AP,OA
R.T.Find:OP
BY THEORM,
17^2=15^2+OP^2
289=225+OP^2
289-225=OP^2
OP^2=64
OP=√64
OP=8 cm...
so,distance from center to chord is 8 cm....
hope it helps...
: )
PLEASE MARK ME BRAINLIST
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