A chord of length 14 cm is at the distance of 6 cm of a circle .The length of another chord at a distance of 2 cm from the center is
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Answer:
Let AB and CD be two chords of the circle.
Draw OM perpendicular to AB and ON = CD
AB = 14 cm
OM = 6 cm
ON = 2 cm
Let,
CD = x
In
AOM,
AO2 = AM2 + OM2
= 72 + 62
AO2 = 85 (i)
In
CON,
CO2 = ON2 + CN2
CO2 = 4 +
(ii)
We Know,
AO = CO
AO2 = CO2
85 = 4 +
x2 = 324
x = 18 cm
so 18 cm is your answer
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