A chord of length 16 cm is at a distance of 6cm from the centre of a circle . Find the radius of a circle
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Answer:
Radius = 10 cm
Step-by-step explanation
In the given figure
Chord AB = 16 cm, Perpendicular distance = 6 cm
A perpendicular from the centre of circle bisects the chord
Therefore, AC = 16 / 2 = 8 cm
In Triangle ACO,
AC = 8 cm
OC = 6 cm
OA = ?
According to pythagoras theorm
OA² = AC² + OC²
OA² = (8)² + (6)²
OA² = 64 + 36
OA² = 100
OA = √100
OA = 10 cm
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A chord of length 16 cm is at a distance 6 cm from the centre of the circle. Find the length of the chord of the same circle which is at a distance 8 cm from the centre.
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