Question

A chord of length 16 cm is drawn in a circle of radius 10 cm . Find the distance of the chord from the centre of the circle​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

Construct the figure

Let AB be a chord of the given circle with centre O and radius 10cm. then OA=10cm and AB=16cm.

Let O be the center of the the circle and AB be the Chord. Draw OL ⊥ AB.

It is known that the perpendicular from the center of a circle to a chord bisects the chord,

Then, AL = $\frac{1}{2}$ × AB

= $\frac{1}{2}$ × 16 = 8 cm

Use Pythagoras theorem, for right - angled.

OL² = OA² - AL²

      = (10)² - (8)²

OL² = 100 - 64

=> OL = √36

OL = 6 cm.