Question

A chord of length 16 cm is drawn in a circle of radius 10 cm, the distance of the chord from the center of the circle is ?​

Answer 1

Answer:

Radius=OA=10cm.

AB is the chord drawn with the length=16 cm.

We know,

perpendicular drawn from the centre of the circle to the chord ,bisects the chord

hence, C is the midpoint of AB.

Therefore,

AC=

2

AB

=

2

16

=8

So using Pythagorean Theorem:

OA

2

=OC

2

+AC

2

10

2

=OC

2

+8

2

100=OC

2

+64

OC

2

=36

OC=6cm

Answer 2

Answer:

Refer to the above attachment.

Distance between the centre of the circle and the chord is

$d = \sqrt{ {10}^{2} - {8}^{2} } = \sqrt{100 - 64} = \sqrt{36} = 6cm$

6cm is the right answer.