A chord of length 48 cm is at a distance of 7 cm from the center of a circle what is the radius of circle
Answers
Answer:
radius=25cm
Step-by-step explanation:
From the figure attached :
Construction: Join OC and OD (after drawing the figure attached to this answer(can be drawn any way )!!!)
given the length of chord AB=48cm. In the figure O is the center
given OQ=7cm
As the 7cm distance is drawn from the center of the circle to the chord then this chord will be divided into half then CQ= 48/2=24cm and QD=48/2=24cm.
taking ΔODQ -here we should find OD which is the radius of the circle
using then using the pythagorean theorem :
( hypotenuse)^2=(base)^2+(altitude)^2
= ( hypotenuse)^2=(QD)^2+OQ^2
=( hypotenuse)^2= 24^2+7^2
=( hypotenuse)^2= 576+49
=( hypotenuse)^2=625
hypotenuse=√625.
=25cm
Therefore hypotenuse=radius of the circle =25cm.
Hope it helps you:)
Please refer the attached pic for the diagram.
Answer:
As the 7cm distance is drawn from the center of the circle to the chord then this chord will be divided into half then CQ= 48/2=24cm and QD=48/2=24cm. hypotenuse=√625. Therefore hypotenuse=radius of the circle =25cm