a chord of length 48 cm is drawn at a distance of 7cm from the centre of circle . calculate the radius of the circle
AB is the chord of circle with centre O and radius OA
OM is perpendicular to AB
Therefore, AB=48cm
OA=7cm
OM⊥AB
M is the mid-point of AB
AM = 1/2 AB = 1/2×48=24cm
Now right △OAM,
OA2=OM2+AM2
(by Pythagoras Axiom)
(7)2=OM2+(24)2
OM2=(7)2−(24)2=625−576
=572=(7)2
OM=25cm
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AB is the chord of circle with centre O and radius OA
OM is perpendicular to AB
Therefore, AB=48cm
OA=7cm
OM⊥AB
M is the mid-point of AB
AM = 1/2 AB = 1/2×48=24cm
Now right △OAM,
OA2=OM2+AM2
(by Pythagoras Axiom)
(7)2=OM2+(24)2
OM2=(7)2−(24)2=625−576
=572=(7)2
OM=25cm
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