Question

A chord of length 48 cm is drawn in a circle of radius 25 cm. Calculate its distance
from the centre of the circle.​

Answer 1

Answer:

AB is the chord of circle with centre O and radius OA

OM is perpendicular to AB

Therefore, AB=48cm

OA=25cm

OM⊥AB

M is the mid-point of AB

AM = 1/2 AB = 1/2×48=24cm

Now right △OAM,

OA

2

=OM

2

+AM

2

(by Pythagoras Axiom)

(25)

2

=OM

2

+(24)

2

OM

2

=(25)

2

−(24)

2

=625−576

=49=(7)

2

OM=7cm