A chord of length 48cm is drawn in a circle of radius 25cm. Calculate its distance from the centre of the circle
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Answer:
AB is the chord of circle with centre O and radius OA
OM is perpendicular to AB
Therefore, AB=48cm
OA=25cm
OM⊥AB
M is the mid-point of AB
AM = 1/2 AB = 1/2×48=24cm
Now right △OAM,
OA
2
=OM
2
+AM
2
(by Pythagoras Axiom)
(25)
2
=OM
2
+(24)
2
OM
2
=(25)
2
−(24)
2
=625−576
=49=(7)
2
OM=7cm
solution
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