A chord of length 6 cm is drawn in a circle of radius 5cm . calculate it's distance from the centre of the circle
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Let AB be the chord and O be the centre of the circle
Let OC be the perpendicular drawn from O to AB
We know, that the perpendicular to a chord, from the centre of a circle, bisects the chord.
∴AC=CB= 6/2 =3 cm
In △OCA,
OA² =OC² +AC ² (BY Pythagoras theorem)
⇒OC ² =(5)²−(3) ²=16
⇒OC=4 cm
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