Question

a chord of length 6cm is drawn in a circle of radius 5 cm calculate its distance from the centre of the circle ​

Answer 1

Answer:

its answer is 4cm

Step-by-step explanation:

in the figure through construction oc perpendicular to ab so in triangle abc angle BAC will be equal to 90 degree AND and by theorem line segment perpendicular drawn to the chord from the centre bisects it so AC is equal to CB equal to 3 cm

now in triangle OAC BY PYTH . THEOREM OA^2 =OC^2+AC^2

5

${5}^{2} = {oc}^{2} + {3}^{2}$

${5}^{2} - {3}^{2} = {oc}^{2}$

so

$oc = \sqrt{16}$

$oc = 4cm$