Question

a chord of length 8cm is at a distance of 3cm from the center.Find the radius of the circle

Answer 1

draw a perpendicular to chord.
hslf of chord =4
by pythagorous thm
r^2 =3^2+4^2
r^2=9+16
r^2=25
r=5 cm

Answer 2

Answer:

The radius of the circle is 5 cm.

Step-by-step explanation:

The length of chord is 8 cm and the distance of chord from the center is 3 cm.

Use Pythagoras theorem in triangle OAB,

$OA^2=AB^2+OB^2$

$r^2=4^2+3^2$

$r^2=16+9$

$r^2=25$

Taking square root both the sides.

$r=\sqrt{25}$

$r=5$

Therefore the radius of the circle is 5 cm.