A Chord of of length 8cm is drawn at a
distance
of 3cm
from the centre of
the circle
Then radius
from the centre
is
Answers
Answered by
0
Answer:
We know, that the perpendicular to a chord, from the centre of a circle, bisects the chord. Hence, radius of the circle is 5 cm.
Answered by
4
Answer:
Radius=5cm
Step-by-step explanation:
Let radius be AB and the centre be A and chord be DB
Perpendicular drawn from center of the circle on the chord bisects the chord
EB=1/2*DB
EB=4 cm
In right angled triangle AEB,
(AB) ^2=EB^2+AE^2
(AB)^2=16+9
(AB)^2=25
AB=5cm
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