A chord of radius 10 cm subtends a right angle at the centre.find the area of the corresponding.
1) minor segment
2) major segment
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given radius=10cm
angle =90degree
area of minor segment
area of sector-area of right triangle
90/360×πr^2-1/2×10×10
1/4×22/7×10×10-50
1100/14-50
550/7-50
550-350/7
200/7
area of major segment=πr^2-200/7
22/7×10×10-200/7
2200/7-200/7
2000/7
angle =90degree
area of minor segment
area of sector-area of right triangle
90/360×πr^2-1/2×10×10
1/4×22/7×10×10-50
1100/14-50
550/7-50
550-350/7
200/7
area of major segment=πr^2-200/7
22/7×10×10-200/7
2200/7-200/7
2000/7
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