a chord pq of a circle of radius 10 cm subtends an angle of 60 at the centre of the circle
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The radius of the circle = 10 cm.
Chord PQ subtends an angle = 60 deg at the centre.
PQO is an equilateral triangle, O being the centre of the circle.
The segment PQO = 1/6 of the area of the circle = (1/6)(22/7)*10^2 = 52.38085238 sq cm.
Triangle POQ = [10^2*sin 60]/2 = 43.30127019 sq cm.
The minor sector = 52.38085238 - 43.30127019 = 9.07958219 sq cm.
The major sector = 6*52.38085238 - 9.07958219 = 305.2055321 sq cm ....
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Seems like your question is incomplete.
Here is the complete question.
Question :- A chord pq of a circle of radius 10 cm subtends an angle of 60 at the centre of the circle. Find the area of the major and minor segment.
Answer is given below.
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