Question

. A chord PQ of a circle whose centre is O, is bisected at R by a diameter ST, given OT (radius)= 15cm and OR = 9cm. Calculate length of PQ. (4)









plz tell fast​

Answer 1

Answer:

pq=24

Step-by-step explanation:

or = 9cm and oq= r= 15cm

and oqr is a right angle triangle

there for by phythagorus theram

oq2=or2+qr2

therefor 15*15=9*9+qr2

225=81+qr2

225-81=qr2

qr2=144

qr=12

qr =pr =12

pq=24

hope it helped pls make it brilliant ans

Answer 2

Answer:

hey mate ur answer is 24.