Question

A chord PQ of a circle with radius 15 cm subtends an angle of 60° with the
centre of the circle. Find the area of the minor as well as the major segment.
(n = 3.14, V3 = 1.73)​

Answer 1

Answer:

Step-by-step explanation:

Area of the minor sector=°/360×2πr

=60/360×2×3.14×15

=1/6×2×3.14×15

=15.7

Area of circle =πr²

=3.14×15²

706.5

Area of major sector =area of circle -area of minor arc

=690.8

Plsss mark as branliest