Question

A chord subtends an angle of 90°at the centre of a circle whose chord is 20 cm. Compute the area of the corresponding major segment of the circle.​

Answer 1

Area of the sector = θ/360 × π × r^2

Base and height of the triangle formed will be = radius of the circle

Area of the minor segment = area of the sector – area of the triangle formed

Area of the major segment = area of the circle – area of the minor segment

Now,

Radius of circle = r = 20 cm and

Angle subtended = θ = 90°

Area of the sector = θ/360 × π × r2 = 90/360 × 22/7 × 20^2

Or, area of the sector = 314.2 cm^2

Area of the triangle = ½ × base × height = ½ × 20 × 20 = 200 cm^2

Area of the minor segment = 314.2 – 200 = 114.2 cm^2

Area of the circle = π × r^2 = (22/7) × 202 = 1257.14

Area of the major segment = 1257.14 – 114.2 = 1142 .94 cm^2

So, the area of the corresponding major segment of the circle = 1142 .94 cm^2

Answer 2

Answer:

Area of major segment = 1142cm^2

Area of minor segment = 114 cm^2

Explanation:

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