A circal is inscribed in a triangle ABC.it touches the sides AB, BC and AC at points R, P and Q respectively.if AQ =4.5cm PC=5.5 cm and ER=6 cm.then the perimeter of the triangle ABC is?
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10
Perimeter of triangle = a+b+c
=4.5+5.5+6cm
=16cm
Therefore the perimeter of the triangle is 16cm.
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Answered by
8
The area of ΔABC is 32cm.
If the external point of the Δ is A, then
AQ = AR, Where AQ = 4.5 cm, thus AR = 4.5cm
Similarly,
If the external point of the Δ is C, then
PC = CQ, Where PC = 5.5 cm, thus CA = 5.5cm
If the external point of the Δ is B, then
PB = ER, Where ER = 6 cm, thus PB = 6 cm
Perimeter of Δ ABC
= 4.5 + 4.5 + 6 + 6 + 5.5 + 5.5
= 32
Thus, the area of ΔABC is 32cm.
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