Question

a circket ball mass 150 g moving at a speed of 25 ms-1 is brought to rest by a player in 0.03s find the average force applied by player​

Answer 1

Explanation:

v=u+at

0=25+a(0.03)

a= -2500/3 m/s2

F=ma= 0.15kgx-2500/3

F= -125N

hope you will get it.

Answer 2

Given :-

A cricket ball of mass 150g moving at a speed of 25 ms^-1 is bought to rest by a player in 0.03s

To Find :-

Average force

Solution :-

We know that

v = u + at

0 = 25 + a(0.03)

0 - 25 = 0.03a

-25 = 0.03a

-25/0.03 = a

-2500/3 = a

Now

1 kg = 1000 g

150 g = 150/1000 = 0.15 kg

F = ma

F = 0.15 × -2500/3

F = 15/100 × (-2500)/3

F = -125 N