Question

A circket ball of mass 0.1 kg is moving horizontally with a speed of 30 m/s. It strikes a
vertical wall and rebounds with a speed of 20 m/s in the opposite direction. The change
in momentum

Answer 1

Momentum earlier =

$= mass \: \times velocity$

$= 0.1 \: \times \: 30 = 3 \: kg \: m {s}^{ - 2}$

Momentum after =

$= mass \: \times \: velocity$

$= 0.1 \: \times \: 20 = 2 \: kg \: m {s}^{ - 2}$

Therefore, change in momentum = 3 - 2 = 1