A circle described on the line joining the points as diameter cut the x-axis at points whose abscissa are roots of the equation
Answers
Answered by
34
The equation of the circle described on the line joining (0,1) and (a, b) as diameter is:
(x-0)(x-a)+(y-1)(y-b)=0
=> x^2+y^2-ax-y(1+b)+b=0
This meets X-axis at y=0.
Therefore, the abscissae of points where the circle meets X-axis are roots of the equation x^2-ax+b=0
(x-0)(x-a)+(y-1)(y-b)=0
=> x^2+y^2-ax-y(1+b)+b=0
This meets X-axis at y=0.
Therefore, the abscissae of points where the circle meets X-axis are roots of the equation x^2-ax+b=0
Attachments:
Answered by
25
Step-by-step explanation:
hope it helps
mark me has brainliest answers
Attachments:
Similar questions