a circle has 2 parallel chords at a distance of 5cm from the centre of circle find the length of chord in terms of radius
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Step-by-step explanation:
so frist you have draw one circle with two radius and name it as M, N, P, B, tita
next,MN =6cm PQ=8cm radius =ON=OQ=5cm
AN =6/2=3[bcoz the perpendicular drawn from the centre to the chord bisetcs the chord
by Pythagoras therom
5 square =OA square +3 square
so we will get OA = 4cm ..
like that,triangle OBQ OQ =4cm ,OB=3cm
- now AB +AO+ OB =4+3=7cm..
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