Question

A Circle has 24 cm. chord and 26 cm. diameter. What is the length of chord from
centre of that circle ?
​

Answer 1

$\huge{Solution}$

d=26c.m.

r=13c.m. if we draw a hieght to the cord from the center than the cord divided into two parts which are equal

let AB is the chord

and the height touches the chord at point X

than AX = BX

AX=24/2=12cm

OA is the radius which is equal to 13cm

in triangle OAX,measure of OXA =90°

and OA is the hypotenus(h)

AX and OX are touching the right angle v so the are p and b

as to Pythagorean theorem,${h}^2$=${p}^2$+ ${b}^2$

${OA}^2$=${Ax}^2$+${OX}^2$

${13}^2$13^2=${12}^2$12^2+${OX}^2$

169= 144+${OX}^2$

169-144=${OX}^2$

25=${OX}^2$

OX = 5 cm

$<marquee>$

anshikuu❤❤

Answer 2

$\huge{Solution}$

d=26c.m.

r=13c.m. if we draw a hieght to the cord from the center than the cord divided into two parts which are equal

let AB is the chord

and the height touches the chord at point X

than AX = BX

AX=24/2=12cm

OA is the radius which is equal to 13cm

in triangle OAX,measure of OXA =90°

and OA is the hypotenus(h)

AX and OX are touching the right angle v so the are p and b

as to Pythagorean theorem,${h}^2$=${p}^2$+ ${b}^2$

${OA}^2$=${Ax}^2$+${OX}^2$

${13}^2$13^2=${12}^2$12^2+${OX}^2$

169= 144+${OX}^2$

169-144=${OX}^2$

25=${OX}^2$

OX = 5 cm

$<marquee>$

shivanaya ❤ ❤