Question

A circle has a radius of 25cm. Find the distance between two parallel chords which are 48 and 40 cm if
(a) They are opposite sides of the center
(b) Same side of the center

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Answer 1

Answer:

We join OC and OA.

So, OC=OA=25 cm, since OC and OA are radii

ΔOAP and ΔOCQ are right ones, since OP⊥AB at P and OQ⊥CD at Q.

Now AP=

2

1

AB=

2

1

×14 cm =7 cm and

CQ=

2

1

CD=

2

1

×48 cm =24 cm

Since the perpendicular from the centre of a circle to a chord bisects the latter.