Question

A circle has a radius of 4/9 units
and is centered at (−6.2,5.8)
Write the equation of this circle.

Answer 1

Given: Circle of a radius 4/9 units, centered at (−6.2,5.8).

To find: Equation of this circle.

Solution:

• As we have given the radius as 4/ 9 and the point of centre is (−6.2,5.8).
• Since the points are in decimal, so lets convert the points in fractional form

                 -6.2 = -6.2 x 10/10 = -62/10

                 = -31/5

                 5.8 = 5.8 x 10/10 = 58/10

                 = 29/5

• So the points are: (-31/5, 29/5)
• Now we know the equation of circle
• Equation of circle is:

                  (x - x1)² + (y - y1)² = r²

                  here x1 and y1 are the point of radius of the circle.

• So, putting values in equation of the circle:

                (x + 31/5)² + (y - 29/5)² = r²

Answer:

         So the required equation of the circle is :(x + 31/5)² + (y - 29/5)² = r²

Answer 2

Step-by-step explanation:

A circle has a radius of 4/9 units  and is centered at (−6.2,5.8)  Write the equation of this circle.

• Given a circle has a radius of 4/9 unit and centre at (- 6.2 , 5.8). We need to write the equation of this circle.
• The general equation will be (x – c)^2 + (y – k)^2 where (c, k) is the centre and r is the radius.
• Now the equation of the circle will be (x + 6.2)^2 + (y – 5.8)^2 = 16 / 81
• Since the x-coordinate is – 6.2 and so it will be x – (- 6.2) = x + 6.2

Reference link will be

https://brainly.in/question/16335770