Question

A circle has an area equal to 25π cm2 . Its diameter AB coincides with one of the sides of a triangle ACB whose vertex C lies on the circle. Triangle ACB has an area equal to 15 cm2 . What is the area of the portion of the circle which is outside the triangle in cm2?

Answer 1

Answer:

Area of circle = 25pi

Pi r^2 = 25pi

r = 5cm..

d = 10cm..

Step-by-step explanation:

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Answer 2

Area of circle = 25pi

Pi r^2 = 25pi

r = 5cm..

d = 10cm..

Area of triangle = 11...

Since one of the side is the diameter let it be the base..

The vertex c lies on the circle..So the triangle is a right angled triangle...

b = d = 10cm..

So

Area = 1/2 * b * h

We dont know h...

h = 11 * 2 / 10 = 2.2..

Pythagoras theorem...

Hypotenuse = Diameter = 10...

so

Other side = 10^2 - 2.2^2) = 9.755cm..

so

Perimeter = 9.755 + 2.2 + 10 = 21.955 = 22cm......