Question

a circle has centre at origin and a point P(5,0) lies on it.the point Q(6,8) lies outside the circle.state true or false. justify your answer

Answer 1

the center (0.0)
radius length=5
=x^2+y^2=25
=6^2+8^2
=36+64
=100
which is greater than 25
so itli outside of circle

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Answer 2

Answer:

Step-by-step explanation:

Answer :-

True

Explanation :-

Point Q (6, 8) will lie outside the circle if its distance from the centre of circle is greater then the radius of the circle.

Distance between centre O(0, 0) and P(5, 0)

⇒ OP = √(5 - 0)² + (0 - 0)²

⇒ OP = √(5)² + (0)²

⇒ OP = 5

As, point P lies at the circle,

Therefore,

OP = Radius of the circle.

Distance between centre O(0, 0) and Q(6, 8)

⇒ OQ = √(6 - 0)² + (8 - 0)²

⇒ OQ = √(6)² + (8)²

⇒ OQ = √36 + 64

⇒ OQ = √100

⇒ OQ = 10

As OQ is greater OP, therefore , point Q(6, 8) lies outside of the circle.