a circle has radius 25 cm, a chord at distance of 7cm from its centre find chords length
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Answer:
Given ,OD=7cm,OB=25cm
Since OD⊥BC,itbisectsBC,i.eBD=DC
In △OBD,
BD
2
=OB
2
−OD
2
=25
2
−7
2
=625−49=576
⇒BD=
576
=24
∴ChordBC=2×24cm=48
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