Question

A circle having an area of 50.27 is tangent to the coordinate axes. Find the area of the
smaller circle that is tangent to the given circle and to the coordinate axes.

Answer 1

C= 50.27 and C= 2 × pi × r

50.27 = 2 × pi × r (pi = 3.1416)

50.27 ÷ 6.2832 = r

r = 8

Area = pi × r^2 = 3.1416 × 64 = 201 sq ft

BTS AND EXO(◍•ᴗ•◍)❤

Answer 2

Given,

circle has an area or can say the circumference of a circle is 50.27

To Find: The area of the smaller circle that is tangent to the given circle and to the coordinate axes?

explanation:

The formula of circumference,

                                             C = $2$×$\pi$×$r$

where,

             we have a value of Circumference (C) and ($\pi$),

                                             $50.27$ = $2$ × $\pi$ × $r$

                                             $50.27$ = $2$ × $3.14$ × $r$

                                              $50.27$ = $6.28$ × $r$

                                                   $r$ = $\frac{50.27}{6.28}$

                                                   $r$ = $8$

Now,

              Area of the circle (A) = $\pi r^{2}$

                                             A = $3.14$$16$ × $8^{2}$

                                             A = $201$ $sq. ft.$

Hence the area of the smaller circle that is tangent to the given circle and to the coordinate axes is 201 sq.ft.