Math, asked by arnavalok, 7 months ago

A circle having centre in the first quadrant and radius 3 units, touches the yy-axis at the point (0,3) .

This circle has equation

Answers

Answered by mbmitali026
8

the explanation is in the given picture

Attachments:
Answered by SteffiPaul
1

Given,

The radius of the circle = 3 units

Centre = First quadrant

Y-intercept = 3

To find,

The equation of the circle.

Solution,

The equation of the circle is x² +y²-6y.

We can simply find the equation of the circle using the given condition.

(x-h)²+(y-k)² = r²

(x-0)² +(y-3)² = 9

x² +y² +9 - 6y = 9

x² +y²-6y

which is the required equation of the circle.

Hence, x² +y²-6y is the required equation of the circle whose center lies in the first quadrant and radius 3 units, touches the y-axis at the point (0,3).

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