A circle is described with minor axis of the ellipse as diameter if the foci lie on the circle then the eccentricity of the ellipse is
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Answered by
0
Answer:
Hence the line segment joining the foci should also be a diameter. Hence they are equal.
2b=2ae
b=ae
b
2
=a
2
e
2
a
2
(1−e
2
)=a
2
e
2
1−e
2
=e
2
1=2e
2
e
2
=
2
1
e=
2
1
Hence the eccentricity =
2
1
.
Answered by
0
Answer:
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Step-by-step explanation:
The distance between the foci=2ae
The line segment joining the foci is bisected perpendicular by the minor axis.
Hence the line segment joining the foci should also be a diameter. Hence they are equal.
2b=2ae
b=ae
b
2
=a
2
e
2
a
2
(1−e
2
)=a
2
e
2
1−e
2
=e
2
1=2e
2
e
2
=
2
1
e=
2
1
Hence the eccentricity =
2
1
.
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