Question

a circle is drawn touching the sides of ∆ABC AT P,Q,R.If AP+BC=13cm,then perimeter of triangle​

Answer 1

Answer:

40

Step-by-step explanation:

△ABC

AB, BC and AC touches the circle at the point P, Q and R respectively.

∴ BC+AP=AC+PB

⟹ 13+7=AC+PB

⟹ AC=20−PB

Perimeter of △ABC=AB+BC+AC

=AP+PB+13+20−PB

=7+13+20=40

∴ Perimeter of △ABC is 40 cm