a circle is drawn touching the sides of triangle ABC at P ,Q ,R if AP+BC =13 then perimeter of a b c moderator please help because some students spam please answer the question because this is urgent
Answers
Given : circle is drawn touching sides of triangle ABC at P,Q,R.
AP+BC=13
To Find : perimeter of triangle ABC
Solution:
Perimeter of Triangle ABC
= AB + BC + AC
= AP + PB + BQ + CQ + CR + AR
AP = AR Equal Tangent
BP = BQ Equal Tangent
CQ = CR Equal Tangent
= AP + BQ + BQ + QC + CQ + AP
= 2( AP + BQ + QC)
= 2 ( AP + BC)
= 2 (13)
= 26
perimeter of Δ ABC = 26 cm
Learn More:
AB is a line segment and M is its mid point. Semicircle are drawn ...
https://brainly.in/question/8285352
The sides of the triangle are 10 cm, 24cm ,26cm. At each of its ...
https://brainly.in/question/10030659
Answer: 26
Explanation:
FOR THE GIVEN FIGURE THE ANSWER WILL BE
Perimeter of ΔABC
= AB + BC + CA
= AP + PB + BR + RC + CQ + QA
Since the two tangents drawn from a point outside the circle are equidistance, we have A, B and C are the exterior points of the circle.
∴ AP = AQ; BP = BR; CR = CQ
= AP + BR + BR + RC + RC + AP
= 2 (AP + BR + RC)
= 2 (AP + BC)
= 2 ( 13 ) (given)
= 26