Question

A circle is drawn touching the sides of triangle ABC at P,Q,R, if AP+BC = 13CM, THEN perimeter of triangle is 1)26cm 2) 39cm 3)42cm 4) 20cm ​

Answer 1

Answer:

In △ABC

AB, BC and AC touches the circle at the point P, Q and R respectively.

∴ BC+AP=AC+PB

⟹ 13+7=AC+PB

⟹ AC=20−PB

Perimeter of △ABC=AB+BC+AC

=AP+PB+13+20−PB

=7+13+20=40

∴ Perimeter of △ABC is 40 cm.