Question

A circle is drawn with a line as diameter and smaller circle with half the li e as diameter.prove that any chord of the larger circle through the point where the circles meet is bisected by the small circle

Answer 1

AB is the diameter and CD the chord which is equal to the radius and so half of AB. Let the centre be O. If you join C and D to O, and A to C and B to D, you will have three equilateral triangles each side of which is the same as the radius of the circle. The exterior angles CDE and DCE will be 60 degrees, and the third angle of the triangle EDC (which is the same as AEB) = 180 - 60 - 60 = 60 degrees

Answer 2

Answer:

how to prove that any chord of the larger circle through the point where the circle meet is bisected by the small circle..