Question

A circle is drawn with origin of the centre It passes through the point 3,3 what is the radius of the circle

Answer 1

Answer:

Step-by-step explanation:

Equation of a circle passing through the origin is $x^{2} + y^{2} = r^{2}$

Since the circle passes through the point (3,3), it satisfies the equation, i.e

$3^{2} + 3^{2} = r^{2}$

$r^{2} = 18$

r = $\sqrt{18} = 3\sqrt{3}$